solving resistors

If R1 = 95Ω
R2 = 62Ω,
R3 = 7Ω,
R4 = 5Ω,
R5 = 22Ω,
R6 = 68Ω,
First you add up the right side resistors becuase they are in series. so R3+R4+R5=7+5+22=34ohms.
Then you would redraw the circuit with just one resistor instead of three with the resistance 34ohms.
Then you would work out the resistance of R2 and R3 by the parallel formula 1/R1 + 1/R2 = RT
so 1/62 + 1/34 =
Then you would add up all the resistances to get the total resistance.