4 things i found hard in the exam

4 things i found hard in the exam..
well everything in the exam was harder then i thourt it would be and my mind was not set on the exam.

solving resistors

If R1 = 95Ω
R2 = 62Ω,
R3 = 7Ω,
R4 = 5Ω,
R5 = 22Ω,
R6 = 68Ω,
First you add up the right side resistors becuase they are in series. so R3+R4+R5=7+5+22=34ohms.
Then you would redraw the circuit with just one resistor instead of three with the resistance 34ohms.
Then you would work out the resistance of R2 and R3 by the parallel formula 1/R1 + 1/R2 = RT
so 1/62 + 1/34 =
Then you would add up all the resistances to get the total resistance.

spreed sheet

here is my spreed sheet

here is my spread sheet

parallel circuit

Total voltage is the same as the supply voltage on every branch of the circuit.
Total Resistance = 1/R1 + 1/R2 = 1/RT
Current breaks of down the branches of the circuit then rejoins to the supply current.

series circuit

Total Resistance is the all the resistance added together. R1+R2=R3
Total Voltage adds up to the supply voltage
Total current stays the same thought out the hole circuit.